[email protected] , ответ добавлен 19.05.2017 в 08:56

1)
y' = ((2 - x^2/4)^3)' = 3(2 - x^2/4)^2*(2 - x^2/4)' = 
= 3(2 - x^2/4)^2*( - 2x/4) = - 1,5x (2 - x^2/4)^2

2)
sin (3x + pi/4) = 1
3x + pi/4  = pi/2 + 2pik
3x = pi/2 - pi/4 + 2pik
3x = 2pi/4 - pi/4 + 2pik
3x = pi/4 + 2pik
x = pi/12 + (2pik)/3, k ∈ Z

 0